Operator MOD

[SMcNeill]

Maybe this SUPER simple formula will show how it works:

Code: (Select All)

For i = -10 To 10
    Print Steve_ModX(i, 5), Steve_ModX2(i, 5), Steve_ModX3(i, 5)
Next


Function Steve_ModX (num1, num2)
    Steve_ModX = ((num1 Mod num2) + Abs(num2)) Mod num2
End Function


Function Steve_ModX2 (num1, num2)
    Steve_ModX2 = num1 - (Int(num1 / num2) * num2)
End Function

Function Steve_ModX3 (num1, num2)
    Steve_ModX3 = num1 - (num1 \ num2) * num2
End Function

And this even showcases how QB64 gets the answer that it goes for us, with ModX3.  

INT(x / y) is NOT the same as x \ y.