03-15-2023, 03:18 AM
(This post was last modified: 03-15-2023, 03:20 AM by TerryRitchie.)
(03-15-2023, 01:43 AM)SMcNeill Wrote: SHARED a, b, c AS INTEGER
The above is valid, but you're mixing data types. a and b are undefined so they're SINGLE types. c is the only integer type above.
Add this to the main code:
a! = 1
b! = 2
Ah, so it should be done as:
SHARED a AS INTEGER, b AS INTEGER, c AS INTEGER
Yeah, this makes sense.
Update: yep, just tried it, works. I'll pass this information along.
Thanks for sleuthing this out guys.